Question on: JAMB Physics - 1999
Calculate the mass of ice that would melt when 2kg of copper is quickly transferred from boiling water to a block of ice without heat loss;
Specific heat capacity of copper = 400JKg-1K-1
Latent heat of fusion of ice = 3.3 x 105JKg-1
Specific heat capacity of copper = 400JKg-1K-1
Latent heat of fusion of ice = 3.3 x 105JKg-1
A
8/33kg
B
33/80kg
C
80/33kg
D
33/8kg
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Correct Option: A
Heat given off by the copper = MCt
= 2 x 400 x (100 - 0)
Heat absorbed by the ice = ML
= M x 3.3 x 105
Heat lost = Heat gained
∴ M x 3.3 x 105 = 2 x 400 x 100
∴ M = (2 x 400 x 100)/3.3 x 105
= 8/33Kg
= 2 x 400 x (100 - 0)
Heat absorbed by the ice = ML
= M x 3.3 x 105
Heat lost = Heat gained
∴ M x 3.3 x 105 = 2 x 400 x 100
∴ M = (2 x 400 x 100)/3.3 x 105
= 8/33Kg
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